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Jigsaw vs Animated Drunkards

PostPosted: Fri Feb 16, 2007 3:22 pm
by SoulOfPrimus
Ok, Jigsaw (saw movies) has set up a house of horrors for his captives. Each room is designed to hit a weak spot for a particular contestant, but to lure someone in they all contain a booby-trapped keg of beer.

Who will last the longest:
Homer Simpson
Peter Griffin
Phillip J Fry
Carl Brotonanonolewski

Only Rule: If they see someone die, the others want a beer unless that keg killed someone.

Edit: Bender is Immune to much of what could happen so I had to leave him out.

PostPosted: Fri Feb 16, 2007 3:51 pm
by Bluebullet
I give this one to Fry. He's the smartest human beer drinker ever.

Why isn't Bender in here? Bender would win just 'cause he's cool. 8)

PostPosted: Fri Feb 16, 2007 6:05 pm
by SoulOfPrimus
My money would be on Homer.

I say this because he has been through stuff that makes 'X-treme Bloopers 8' look like 'Knitting with Nancy'. I can see Homer cutting through a room of razorline for a donut and have it not even phase him (remember Springfield Gorge?).

As for hitting the booby-trapped keg, Fry and Peter are faster and Carl would of been killed in the first room with boobs.

Re: Jigsaw vs Animated Drunkards

PostPosted: Wed Oct 04, 2023 6:12 am
by snavej
Those toons are indestructible. They win. Jigsaw has to go back to his horrible movies.