The Energon Pub

Fri Feb 16, 2007 3:22 pm

Ok, Jigsaw (saw movies) has set up a house of horrors for his captives. Each room is designed to hit a weak spot for a particular contestant, but to lure someone in they all contain a booby-trapped keg of beer.

Who will last the longest:
Homer Simpson
Peter Griffin
Phillip J Fry
Carl Brotonanonolewski

Only Rule: If they see someone die, the others want a beer unless that keg killed someone.

Edit: Bender is Immune to much of what could happen so I had to leave him out.

Fri Feb 16, 2007 3:51 pm

I give this one to Fry. He's the smartest human beer drinker ever.

Why isn't Bender in here? Bender would win just 'cause he's cool.

Fri Feb 16, 2007 6:05 pm

My money would be on Homer.

I say this because he has been through stuff that makes 'X-treme Bloopers 8' look like 'Knitting with Nancy'. I can see Homer cutting through a room of razorline for a donut and have it not even phase him (remember Springfield Gorge?).

As for hitting the booby-trapped keg, Fry and Peter are faster and Carl would of been killed in the first room with boobs.