Ok, Jigsaw (saw movies) has set up a house of horrors for his captives. Each room is designed to hit a weak spot for a particular contestant, but to lure someone in they all contain a booby-trapped keg of beer.
Who will last the longest:
Homer Simpson
Peter Griffin
Phillip J Fry
Carl Brotonanonolewski
Only Rule: If they see someone die, the others want a beer unless that keg killed someone.
Edit: Bender is Immune to much of what could happen so I had to leave him out.
Jigsaw vs Animated Drunkards
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Jigsaw vs Animated Drunkards
Last edited by SoulOfPrimus on Fri Feb 16, 2007 6:06 pm, edited 1 time in total.
- SoulOfPrimus
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My money would be on Homer.
I say this because he has been through stuff that makes 'X-treme Bloopers 8' look like 'Knitting with Nancy'. I can see Homer cutting through a room of razorline for a donut and have it not even phase him (remember Springfield Gorge?).
As for hitting the booby-trapped keg, Fry and Peter are faster and Carl would of been killed in the first room with boobs.
I say this because he has been through stuff that makes 'X-treme Bloopers 8' look like 'Knitting with Nancy'. I can see Homer cutting through a room of razorline for a donut and have it not even phase him (remember Springfield Gorge?).
As for hitting the booby-trapped keg, Fry and Peter are faster and Carl would of been killed in the first room with boobs.
- SoulOfPrimus
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Re: Jigsaw vs Animated Drunkards
- Motto: "Follow your instincts and your common sense."
Those toons are indestructible. They win. Jigsaw has to go back to his horrible movies.
- snavej
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